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乐綝【破锐】ai 

修复乐綝【破锐】修复遗留的ai问题，并将根据失去牌数选择目标ai的效果加回
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mengxinzxz 2023-08-25 15:56:37 +08:00 committed by GitHub
parent cd59328b19
commit ef7cb4f4ee
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GPG Key ID: 4AEE18F83AFDEB23
1 changed files with 12 additions and 11 deletions
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23
character/huicui.js
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@ -620,31 +620,32 @@ game.import('character',function(lib,game,ui,get,ai,_status){
direct:true,
content:function(){
'step 0'
var map={};
game.countPlayer(function(current){
if(current==player||current==trigger.player) return false;
if(current.hasHistory('lose',function(evt){
return evt.cards2.length>0;
})) map[current.playerid]=Math.min(5,current.getHistory('lose').reduce(function(num,evt){
return num=evt.cards2.length;
},0))+1;
});
player.chooseCardTarget({
prompt:get.prompt('dcporui'),
//prompt2:'弃置一张基本牌并选择一名本回合失去过牌的非当前回合的其他角色，你视为对其依次使用'+get.cnNumber(Math.max(0,player.hp)+1)+'张【杀】',
prompt2:get.skillInfoTranslation('dcporui',player),
filterCard:function(card,player){
return get.type2(card)=='basic'&&lib.filter.cardDiscardable(card,player,'dcporui');
},
position:'he',
filterTarget:function(card,player,target){
return _status.event.list.contains(target);
return Object.keys(_status.event.map).contains(target.playerid);
},
ai1:function(card){
return 7-get.value(card);
},
ai2:function(target){
return get.effect(target,{name:'sha'},_status.event.player,_status.event.player)*_status.event.list.find(i=>{
return i[0]==target;
})[1];
return get.effect(target,{name:'sha'},_status.event.player,_status.event.player)*_status.event.map[target.playerid];
}
}).set('list',game.filterPlayer(current=>{
if(current==player||current==trigger.player) return false;
return current.hasHistory('lose',function(evt){
return evt.cards2.length>0;
});
}));
}).set('map',map);
'step 1'
if(result.bool){
var target=result.targets[0],cards=result.cards;